已知水苯酚系统在（低温时固态部分互溶）

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5 / 3mol水w = pv = nrt，w = 5/3 * 8.314 * 373 = 5.169kj q = 40.66 * 5/3 = 67.77kjh是指相等压力过程的热变化，因此H = Q = 67.77 kj u = h + w = 72.94kj应该是为了帮助你〜
2021-07-03 11:54:36

Lu珊Han
1.已知H2O(l)在373.15K时饱和蒸气压101325Pa，摩尔蒸发焓为40.67kJ·mol,(1) H2O(l) → H2O(g) ， △Hmθ = 40.67kJ·mol-1 K1 = p(H2O)1 / pθ = 101325Pa / 100000Pa = 1.01325 ln(K2/K1) = △Hmθ(T2 - T1) / R·T1·T2 = 40.67×1000J·mol-1×(363.15K - 373.15K) / (8.314J·mol-1·K-1×363.15K×373.15K )= - 0.36171 K2/K1 = 0.69649 K2 = 0.69649 × 1.01325 = 0.70572 p(H2O)2 = K2 × pθ = 0.70572 × 100KPa = 70.572KPa(2) K3 = p(H2O)3 / pθ = 57300Pa / 100000Pa = 0.573 ln(K3/K1) = ln(0.573 / 1.01325) = - 0.57 ln(K3/K1) = (△Hmθ / R)·(1 / T1 - 1 / T3) 1 / T3 = 1 / T1 - [ ln(K3/K1)×R / △Hmθ ] = 1 / 373.15K - (- 0.57)×8.314J·mol-1·K-1/40.67×1000J·mol-1= 0.0028 K-1 T3 = 357.56K = 84.41℃
2021-07-03 11:54:36